If it's not what You are looking for type in the equation solver your own equation and let us solve it.
x^2-5x-450=0
a = 1; b = -5; c = -450;
Δ = b2-4ac
Δ = -52-4·1·(-450)
Δ = 1825
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1825}=\sqrt{25*73}=\sqrt{25}*\sqrt{73}=5\sqrt{73}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-5\sqrt{73}}{2*1}=\frac{5-5\sqrt{73}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+5\sqrt{73}}{2*1}=\frac{5+5\sqrt{73}}{2} $
| 12q+7-3q=8+9q=25=5q= | | 3x^2-4x=172 | | 360=x(4x+5) | | 7(4v-5)=-27 | | x-0.04x=84 | | 180-150p=120-20p | | 2x+3=5x(3 | | 11x-1=7x-17=180 | | -8(4n+2)=-26+7n | | 5x+36=180-3x | | 2h/15=60 | | 11x-1+7x-17=90 | | 20=2(4b+3) | | m+7+m-7=29 | | 90+(5x*2)=180 | | 100-50x=90-20x | | 100-50x=20+90x | | 0.6y-40=0 | | 850(1.098)^x=1500(1.04)^x | | 0=40-15x | | 3x2+8x-203=0 | | F(t)=-t^2+6t | | x^2=180-6x | | 4/8r=1/4 | | 2(2x)+11+2x=47 | | (62)(x)+(64)(1-x)=63 | | 9z-3z=15 | | 1.1m=5.5 | | 12n+8=6n+41 | | 9.8=5x+3.4 | | 78.34÷=n | | 6(x-7.7)=7.8 |